10b^2-61b-132=0

Solution for 10b^2-61b-132=0 equation:

10b^2-61b-132=0

a = 10; b = -61; c = -132;
Δ = b2-4ac
Δ = -612-4·10·(-132)
Δ = 9001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{9001}}{2*10}=\frac{61-\sqrt{9001}}{20}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{9001}}{2*10}=\frac{61+\sqrt{9001}}{20}
$